Each student in KLU is given a matrix and are assigned with few tasks, Rishab being a student of kLU is also given a matrix and is assigned few tasks to perform on matrix but he is not aware of matrices so you being his mate need to get his tasks done.
Task 1- Given a matrix, transpose the matrix and print it.
Task 2- find maximum row sum and maximum column sum of transposed matrix.
Task 3- print absolute difference of maximum row sum and maximum column sum of transposed matrix.\
Input Format
First line consists of dimensions of matrix r,c. Next r line consists of matrix elements.
Constraints
1 < r,c < 10Output Format
first c lines of output consists of transposed matrix. Next line consists of absolute difference of maximum row sum and maximum coloumn sum of transposed matrix.
Sample Input 0
3 3
1 2 3
2 1 3
3 1 2Sample Output 0
1 2 3
2 1 1
3 3 2
2Solution in java
import java.util.Scanner;
class Solution {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int r = sc.nextInt();
int c = sc.nextInt();
int matrix[][] = new int[r][c];
int transpose[][] = new int[c][r];
int max_row_sum = 0;
int max_col_sum = 0;
for (int i = 0; i < r; i++) {
for (int j = 0; j < c; j++) {
matrix[i][j] = sc.nextInt();
}
}
for (int i = 0; i < c; i++) {
int row_sum = 0;
for (int j = 0; j < r; j++) {
transpose[i][j] = matrix[j][i];
row_sum += transpose[i][j];
System.out.print(transpose[i][j] + " ");
}
if (max_row_sum < row_sum)
max_row_sum = row_sum;
System.out.println();
}
for (int i = 0; i < r; i++) {
int col_sum = 0;
for (int j = 0; j < c; j++) {
col_sum += transpose[j][i];
}
if (max_col_sum < col_sum)
max_col_sum = col_sum;
}
System.out.println(Math.abs(max_row_sum - max_col_sum));
sc.close();
}
}