“Contestant who earns a score equal to or greater than the k-th place finisher’s score will advance to the next round, as long as the contestant earns a positive score…” — an excerpt from contest rules.

A total of n participants took part in the contest (n ≥ k), and you already know their scores. Calculate how many participants will advance to the next round.

## Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 50) separated by a single space.

The second line contains n space-separated integers a1, a2, …, an (0 ≤ ai ≤ 100), where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from 1 to n - 1 the following condition is fulfilled: ai ≥ ai + 1).

## Output

Output the number of participants who advance to the next round.

## Examples

```
input
8 5
10 9 8 7 7 7 5 5
output
6
input
4 2
0 0 0 0
output
0
```

## Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.

## Codeforces 158 a Next Round problem solution in java

```
// 158a NextRound
import java.util.Scanner;
public class NextRound {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int k = sc.nextInt();
int[] arr = new int[n];
int count = 0;
for (int i = 0; i < n; i++) {
arr[i] = sc.nextInt();
}
k = arr[k - 1];
for (int i = 0; i < n; i++) {
if (arr[i] >= k && arr[i] > 0)
count++;
else
break;
}
System.out.println(count);
sc.close();
}
}
```